How do you simplify $\sqrt{98}$ $sqrt98$ ?

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Answer 1 · 2016-02-03T08:30:49

$\sqrt{98} = 7 \sqrt{2}$ $sqrt(98) = 7sqrt(2)$

We will use the following properties:
For $a, b \geq 0$ $a, b >= 0$

- $\sqrt{a^{2}} = a$ $sqrt(a^2) = a$

Then, applying this,

$\sqrt{98} = \sqrt{49 \cdot 2}$ $sqrt(98) = sqrt(49*2)$

$= \sqrt{49} \sqrt{2}$ $=sqrt(49)sqrt(2)$

$= \sqrt{7^{2}} \sqrt{2}$ $=sqrt(7^2)sqrt(2)$

$= 7 \sqrt{2}$ $=7sqrt(2)$

How do you simplify √98sqrt98?