How do you simplify $\frac{t^{2} {(t - 11)}^{4}}{t^{5} {(t - 11)}^{2}}$ $(t^2(t-11)^4)/(t^5(t-11)^2)$ ?

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Answer 1 · 2016-09-15T15:08:57

$\frac{{(t - 11)}^{2}}{t^{3}}$ $((t - 11)^(2)) / (t^(3))$

We have: $\frac{t^{2} {(t - 11)}^{4}}{t^{5} {(t - 11)}^{2}}$ $(t^(2) (t - 11)^(4)) / (t^(5) (t - 11)^(2))$

Using the laws of exponents:

$= t^{2 - 5} \cdot {(t - 11)}^{4 - 2}$ $= t^(2 - 5) cdot (t - 11)^(4 - 2)$

$= t^{- 3} \cdot {(t - 11)}^{2}$ $= t^(- 3) cdot (t - 11)^(2)$

$= \frac{{(t - 11)}^{2}}{t^{3}}$ $= ((t - 11)^(2)) / (t^(3))$

How do you simplify (t^2(t-11)^4)/(t^5(t-11)^2)t2(t−11)4t5(t−11)2(t^2(t-11)^4)/(t^5(t-11)^2)?