How do you simplify $tan^2y/secydiv(3tan^3y)/secy$ ?

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Answer 1 · 2016-09-03T14:08:16

$(tan^2y/secy)xx((secy)/(3tan^3y))=1/(3tany)=coty/3$

Remember that when dividing fractions, it's the same as multiplying by the inverse. And so this:

$(tan^2y/secy)-:((3tan^3y)/secy)$ becomes

$(tan^2y/secy)xx((secy)/(3tan^3y))$

cancel out terms to get

$(tan^2y/secy)xx((secy)/(3tan^3y))=1/(3tany)=coty/3$

How do you simplify tan^2y/secydiv(3tan^3y)/secytan^2y/secydiv(3tan^3y)/secy?