How do you simplify $(tan2x)/(2tanx)-sec^2x/(1-tan^2x)$ ?

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Answer 1 · 2016-09-23T09:12:25

$(tan2x)/(2tanx)-sec^2x/(1-tan^2x)$

$=(2tanx)/((2tanx)(1-tan^2x))-sec^2x/(1-tan^2x)$

$=1/(1-tan^2x)-sec^2x/(1-tan^2x)$

$=(1-sec^2x)/(1-tan^2x)$

$=(1-1-tan^2x)/(1-tan^2x)$

$=tan^2x/(tan^2x-1)$

How do you simplify (tan2x)/(2tanx)-sec^2x/(1-tan^2x)(tan2x)/(2tanx)-sec^2x/(1-tan^2x)?