How do you simplify $tan A sin A + cos A$ $tanA sinA + cosA$ ?

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How do you simplify $tan A sin A + cos A$ $tanA sinA + cosA$ ?

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Answer 1 · 2015-11-04T05:22:05

It is

$tan A \cdot sin A + cos A = \frac{sin A}{cos A} \cdot sin A + cos A = \frac{{sin}^{2} A + {cos}^{2} A}{cos A} = \frac{1}{cos A}$ $tanA*sinA+cosA=sinA/cosA*sinA+cosA=(sin^2A+cos^2A)/(cosA)=1/cosA$

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How do you simplify $tan A sin A + cos A$ $tanA sinA + cosA$ ?

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How do you simplify $tan A sin A + cos A$ $tanA sinA + cosA$ ?