How do you simplify $\frac{tan x}{sin x} + \frac{1}{cos x}$ $tanx/sinx+1/cosx$ ?

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How do you simplify $\frac{tan x}{sin x} + \frac{1}{cos x}$ $tanx/sinx+1/cosx$ ?

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Answer 1 · 2015-04-15T19:34:07

You can write $tan (x) = \frac{sin (x)}{cos (x)}$ $tan(x)=sin(x)/cos(x)$ and get:
$\frac{sin (x)}{cos (x)} \cdot \frac{1}{sin (x)} + \frac{1}{cos (x)} = \frac{1}{cos (x)} + \frac{1}{cos (x)} = \frac{2}{cos (x)}$ $sin(x)/cos(x)*1/sin(x)+1/cos(x)=1/cos(x)+1/cos(x)=2/cos(x)$

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How do you simplify $\frac{tan x}{sin x} + \frac{1}{cos x}$ $tanx/sinx+1/cosx$ ?

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How do you simplify $\frac{tan x}{sin x} + \frac{1}{cos x}$ $tanx/sinx+1/cosx$ ?