How do you simplify the expression $\frac{1 - sec x}{{sec}^{2} x - 1}$ $(1-secx)/(sec^2x-1)$ ?

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Answer 1 · 2016-11-25T09:28:01

$= - \frac{1}{1 + sec x}$ $=-1/(1+secx)$

$\frac{1 - sec x}{{sec}^{2} x - 1}$ $(1-secx)/(sec^2x-1)$

providing ${sec}^{2} x \neq 1$ $" " sec^2x!=1$

$= \frac{1 - sec x}{- (1 - {sec}^{2} x)}$ $=(1-secx)/-(1-sec^2x)$

$=-cancel((1-secx))/((cancel(1-secx))(1+secx))$

$=-1/(1+secx)$

How do you simplify the expression (1-secx)/(sec^2x-1)1−secxsec2x−1(1-secx)/(sec^2x-1)?