How do you simplify the expression $1+tan^2theta$ ?

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Answer 1 · 2018-07-16T11:36:19

The answer is $=sec^2theta$

We need

$tantheta=sintheta/costheta$

$sin^2theta+cos^2theta=1$

$1/costheta=sectheta$

The expression is

$1+tan^2theta=1+sin^2theta/cos^2theta$

$=(cos^2theta+sin^2theta)/cos^2theta$

$=1/cos^2theta$

$=sec^2theta$

Answer 2 · 2018-07-16T11:37:36

$1+\tan^2\theta=\sec^2\theta$

$1+\tan^2\theta$

$=1+\sin^2\theta/\cos^2\theta$

$={\cos^2\theta+\sin^2\theta}/\cos^2\theta$

$={1}/\cos^2\theta$

$=\sec^2\theta$

How do you simplify the expression 1+tan^2theta1+tan^2theta?