How do you simplify the expression $3 \sqrt{2 x^{2} y}$ $3sqrt(2x^2y)$ ?

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Answer 1 · 2016-03-26T05:42:07

$3 \sqrt{2 x^{2} y} = 3 x \sqrt{2 y}$ $3sqrt(2x^2y)=3xsqrt(2y)$

Just divide the root and then cancel the root with the square through the properties:

$\sqrt{a \cdot b} = \sqrt{a} \cdot \sqrt{b}$ $sqrt(a*b)=sqrt(a)*sqrt(b)$

$\sqrt{a^{2}} = a$ $sqrt(a^2)=a$

Solution:

$3 \sqrt{2 x^{2} y} = 3 \sqrt{x^{2} \cdot 2 y} = 3 \sqrt{x^{2}} \sqrt{2 y} =$ $3sqrt(2x^2y)=3sqrt(x^2*2y)=3sqrt(x^2)sqrt(2y)=$

$= 3 x \sqrt{2 y}$ $=3xsqrt(2y)$

How do you simplify the expression 3sqrt(2x^2y)3√2x2y3sqrt(2x^2y)?