How do you simplify the expression cos^2x/(1+sinx)cos2x1+sinx?

1 Answer
Cesareo R.
Sep 27, 2016

1-sin x1−sinx

Explanation:

cos^2x/(1+sinx) = (1-sin^2 x)/(1+sinx) = ((1-sin x)(1+sin x))/(1+sin x)cos2x1+sinx=1−sin2x1+sinx=(1−sinx)(1+sinx)1+sinx

Now we proceed to cancell (1+sin x)(1+sinx) in both numerator and denominator because they configure a so called avoidable discontinuity. So

cos^2x/(1+sinx) = 1-sin xcos2x1+sinx=1−sinx

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