How do you simplify the expression cos(arcsin(x/5)) ?

1 Answer
Jul 18, 2016

cos(arcsin(\frac{x}{5})) = \frac{sqrt{25-x^2}}{5}.

Explanation:

Firstly, note that for the range of arcsin(\frac{x}{5}), the cosine function is purely positive.

Thus, I can say,

cos(arcsin(\frac{x}{5})) = sqrt{1-sin^2(arcsin(\frac{x}{5}))}, and also for the domain of x, sin(arcsin(\frac{x}{5})) = \frac{x}{5} since the arcsine function outputs values ranging from -\frac{pi}{2} to \frac{pi}{2}.

This can be verified graphically, the red one being cos(arcsin(\frac{x}{5})), green cos(\frac{x}{5}), and blue arcsin(\frac{x}{5}): enter image source here

Therefore,

cos(arcsin(\frac{x}{5})) = sqrt{1-\frac{x^2}{25})

= \frac{sqrt{25-x^2}}{5}.