How do you simplify the expression $cot(arctan (1/x))$ ?

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Answer 1 · 2016-07-20T11:49:14

x

If $tan a =1/x. cot a = x$ .

So, $cot tan(1/x)$

= cotangent of the angle whose tangent is (1/x)

= cotangent of the angle whose cotangent is x

= x..

How do you simplify the expression cot(arctan (1/x))cot(arctan (1/x))?