How do you simplify the expression $cot x cos x + {cot}^{2} x$ $cotxcosx+cot^2x$ ?

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Answer 1 · 2018-04-23T16:49:01

$\frac{{cos}^{2} x (sin x + 1)}{{sin}^{2} x}$ ${cos^2x(sinx+1)}/sin^2x$ .

$cot x cos x + {cot}^{2} x$ $cotxcosx+cot^2x$ ,

$= \frac{cos x}{sin x} \cdot cos x + \frac{{cos}^{2} x}{{sin}^{2} x}$ $=cosx/sinx*cosx+cos^2x/sin^2x$ ,

$= \frac{{cos}^{2} x}{sin x} + \frac{{cos}^{2} x}{{sin}^{2} x}$ $=cos^2x/sinx+cos^2x/sin^2x$ ,

$= \frac{{cos}^{2} x sin x + {cos}^{2} x}{{sin}^{2} x}$ $=(cos^2xsinx+cos^2x)/sin^2x$ ,

$= \frac{{cos}^{2} x (sin x + 1)}{{sin}^{2} x}$ $={cos^2x(sinx+1)}/sin^2x$ .

How do you simplify the expression cotxcosx+cot^2xcotxcosx+cot2xcotxcosx+cot^2x?