How do you simplify the expression $(sin^3t+cos^3t)/(1-sintcost)$ ?

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Answer 1 · 2016-10-26T10:30:09

$(sin^3t+cos^3t)/(1-sintcost)=sint+cost$

To simplify $(sin^3t+cos^3t)/(1-sintcost)$ , we use the identity

$(a^3+b^3)=(a+b)(a^2+b^2-ab)$ . Using this

$(sin^3t+cos^3t)/(1-sintcost)$

= $((sint+cost)(sin^2t+cos^2t-sintcost))/(1-sintcost)$

= $((sint+cost)(1-sintcost))/(1-sintcost)$

= $(sint+cost)$

How do you simplify the expression (sin^3t+cos^3t)/(1-sintcost)(sin^3t+cos^3t)/(1-sintcost)?