How do you simplify the expression $(sinx+cosx)/(sinxcosx)$ ?

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Answer 1 · 2018-04-03T03:46:06

$(sinx+cosx)/(sinxcosx)=color(red)(secx+cscx)$

(see simplification process below)

$(sinx+cosx)/(sinxcosx)$

$rArrsinx/(sinxcosx)+cosx/(sinxcosx)$

$rArrcancelsinx/(cancelsinxcosx)+cancelcosx/(sinxcancelcosx)$

$rArr1/cosx+1/sinx$

$rArrcolor(red)(secx+cscx)$

Answer 2 · 2018-04-03T03:49:19

sec x + csc x

$(sin x + cos x)/(sin x.cos x) =$
$= (sin x)/(sin x.cos x) + (cos x)/(sin x.cos x)= = sec x + csc x$

How do you simplify the expression (sinx+cosx)/(sinxcosx)(sinx+cosx)/(sinxcosx)?