How do you simplify the expression $\sqrt{- 64 x^{4}}$ $sqrt(-64x^4)$ ?

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Answer 1 · 2016-04-15T15:58:03

$\Rightarrow 8 x^{2} i$ $=>8x^2 i$

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As soon as you see a negative value to have its square root calculated you know that complex numbers are involves.

Write as $\sqrt{(- 1) \times 8^{2} \times x^{2} \times x^{2}}$ $sqrt( (-1)xx8^2xx x^2xx x^2)$

$\Rightarrow 8 \times x \times x \times \sqrt{- 1} = 8 x^{2} \sqrt{- 1}$ $=>8xx x xx x xx sqrt(-1)" " =" " 8x^2sqrt(-1)$

But $\sqrt{- 1} = i$ $sqrt(-1) = i$

$\Rightarrow 8 x^{2} i$ $=>8x^2 i$

How do you simplify the expression √−64x4sqrt(-64x^4)?