How do you simplify the expression $\frac{{tan}^{2} θ}{sec θ + 1} + 1$ $tan^2theta/(sectheta+1)+1$ ?

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How do you simplify the expression $\frac{{tan}^{2} θ}{sec θ + 1} + 1$ $tan^2theta/(sectheta+1)+1$ ?

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Answer 1 · 2016-11-10T17:32:34

$sec θ$ $sec theta$

Explanation:

Use ${tan}^{2} θ = {sec}^{2} θ - 1$ $tan^2 theta = sec^2 theta -1$ to get
$\frac{{tan}^{2} θ}{sec θ + 1} + 1 = \frac{{sec}^{2} θ - 1}{sec θ + 1} + 1 = (sec θ - 1) + 1 = sec θ$ $tan^2theta/(sectheta+1)+1 ={sec^2theta-1}/(sec theta+1)+1 = (sectheta -1)+1 = sectheta$

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How do you simplify the expression $\frac{{tan}^{2} θ}{sec θ + 1} + 1$ $tan^2theta/(sectheta+1)+1$ ?

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How do you simplify the expression tan2θsecθ+1+1tan^2theta/(sectheta+1)+1?

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Explanation:

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How do you simplify the expression $\frac{{tan}^{2} θ}{sec θ + 1} + 1$ $tan^2theta/(sectheta+1)+1$ ?