How do you simplify the radical expression $\sqrt{32 x^{5}}$ $sqrt(32x^5)$ ?

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Answer 1 · 2017-04-20T09:05:29

$4 x^{2} \sqrt{2 x}$ $4x^2sqrt(2x)$

Write down your equation as
$\sqrt{(16 x^{4}) (2 x)}$ $sqrt((16x^4)(2x)$

Now take the first term out:
$4 x^{2} \sqrt{2 x}$ $4x^2sqrt(2x)$

This is the simple form of your equation
$4 x^{2} \sqrt{2 x}$ $4x^2sqrt(2x)$

Answer 2 · 2017-04-20T10:47:21

$4 x^{2} \sqrt{2 x}$ $color(green)(4x^2sqrt(2x)$

$\sqrt{32 x^{5}}$ $sqrt(32x^5)$

$:.sqrt(4*4*2*x*x*x*x*x$

$:.sqrt4*sqrt4=4$

$:.sqrtx*sqrtx=x$

$:.4*x*x*sqrt(2*x)$

$:.color(green)(4x^2sqrt(2x)$

How do you simplify the radical expression sqrt(32x^5)√32x5sqrt(32x^5)?