How do you simplify this expression $4 c^{4} \sqrt{64 c^{9} x^{6}}$ $4c^4sqrt(64c^9 x^6)$ ?

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Answer 1 · 2018-03-24T15:38:27

$\Rightarrow 32 c^{\frac{17}{2}} x^{3}$ $=>32c^(17/2)x^3$

We start with:

$4 c^{4} \sqrt{64 c^{9} x^{6}}$ $4c^4sqrt(64c^9 x^6)$

Taking the square root is equivalent to raising to the $\frac{1}{2}$ $1/2$ power.

$\Rightarrow 4 c^{4} {(64 c^{9} x^{6})}^{\frac{1}{2}}$ $=>4c^4(64c^9x^6)^(1/2)$

$\Rightarrow 4 c^{4} (8 c^{\frac{9}{2}} x^{3})$ $=>4c^4(8c^(9/2)x^3)$

Now we distribute the $4 c^{4}$ $4c^4$ into the quantity we took the square root of.

$\Rightarrow 32 c^{(4 + \frac{9}{2})} x^{3}$ $=>32c^((4+9/2))x^(3)$

$\Rightarrow 32 c^{\frac{17}{2}} x^{3}$ $=>32c^(17/2)x^3$

How do you simplify this expression 4c^4sqrt(64c^9 x^6)4c4√64c9x64c^4sqrt(64c^9 x^6)?