How do you simplify $(x^{2} + 1) - (3 x^{2} - 4 x + 3)$ $(x^2 + 1)- (3x^2 - 4x + 3)$ ?

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Answer 1 · 2016-09-27T20:43:47

$= - 2 x^{2} + 4 x - 2$ $=-2x^2 +4x -2$

$(x^{2} + 1) - (3 x^{2} - 4 x + 3) \leftarrow$ $(x^2 + 1)- (3x^2 - 4x + 3)" "larr$ remove brackets. Watch signs!

$= x^{2} + 1 - 3 x^{2} + 4 x - 3 \leftarrow$ $=x^2 + 1-3x^2 + 4x - 3" "larr$ collect like terms.

$= x^{2} - 3 x^{2} + 4 x + 1 - 3$ $=x^2-3x^2+4x+1-3$

$= - 2 x^{2} + 4 x - 2$ $=-2x^2 +4x -2$

How do you simplify (x2+1)−(3x2−4x+3)(x^2 + 1)- (3x^2 - 4x + 3)?