How do you simplify ${(x^{- 2})}^{3}$ $(x^-2)^3$ ?

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How do you simplify ${(x^{- 2})}^{3}$ $(x^-2)^3$ ?

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Answer 1 · 2017-02-13T13:10:45

See the entire simplification process below:

Explanation:

Use this rule of exponents to simplify: ${(x^{a})}^{b} = x^{a \times b}$ $(x^color(red)(a))^color(blue)(b) = x^(color(red)(a) xx color(blue)(b))$

${(x^{- 2})}^{3} = x^{- 2 \times 3} = x^{- 6}$ $(x^color(red)(-2))^color(blue)(3) = x^(color(red)(-2) xx color(blue)(3)) = x^-6$

If as part of the simplification process you want to have only positive exponents you can use this rule for exponents: $x^{a} = \frac{1}{x^{- a}}$ $x^color(red)(a) = 1/x^color(red)(-a)$

$x^{- 6} = \frac{1}{x^{- - 6}} = \frac{1}{x^{6}}$ $x^color(red)(-6) = 1/x^color(red)(- -6) = 1/x^6$

The simplification is $x^{- 6}$ $x^-6$ or $\frac{1}{x^{6}}$ $1/x^6$

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How do you simplify ${(x^{- 2})}^{3}$ $(x^-2)^3$ ?

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Explanation:

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How do you simplify (x−2)3(x^-2)^3?

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How do you simplify ${(x^{- 2})}^{3}$ $(x^-2)^3$ ?