How do you simplify $\frac{x^{2} + 4 x + 4}{x^{2} - 4}$ $(x^2+4x+4)/(x^2-4)$ ?

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Answer 1 · 2016-07-10T05:37:46

The answer is $\frac{x + 2}{x - 2}$ $(x+2)/(x-2)$

First, you need to get the factors of the numerator and the denominator.

$\frac{x^{2} + 4 x + 4}{x^{2} - 4}$ $(x^2+4x+4)/(x^2-4)$

$\frac{(x + 2) (x + 2)}{(x + 2) (x - 2)}$ $[(x+2)(x+2)]/[(x+2)(x-2)]$

Since x+2 is divisible by x+2, they will be cancelled.

And the answer is: $\frac{x + 2}{x - 2}$ $(x+2)/(x-2)$

How do you simplify x2+4x+4x2−4(x^2+4x+4)/(x^2-4)?