How do you simplify $(x^2 + 7x - 5) - (3x^2 + 1)$ ?

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Answer 1 · 2016-10-02T17:04:49

(x-2)(3-2x)

$(x^2+7x-5)-(3x^2+1)$
= $x^2+7x-5-3x^2-1$
= $-2x^2+7x-6$
= $-2x^2+4x+3x-6$
= -2x(x-2)+3(x-2)
= (x-2)(-2x+3)
= (x-2)(3-2x)

How do you simplify (x^2 + 7x - 5) - (3x^2 + 1)(x^2 + 7x - 5) - (3x^2 + 1)?