Question

How do you simplify `( x^2 )/(xy^-4)*(2x^-3y^4)/( 3xy^-1)`?

Answer 1

`(2y^9)/(3x^3)`

Explanation:

`(x^2)/(xy^-4) * (2x^-3y^4)/(3xy^-1)`

We start by moving the negative exponents into positive reciprocals.

`(x^2y^4)/x * (2y^5)/(3x^4)`

We can cancel a `x^2` from the numerator and denominator.
`y^4/x * (2y^5)/(3x^2)`

`(2y^9)/(3x^3)`