How do you simplify ${(x^{2} \cdot y^{3})}^{5}$ $(x^2 * y^3) ^5$ ?

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Answer 1 · 2017-03-16T00:48:12

$x^{10} y^{15}$ $x^{10}y^{15}$

Know that: ${(x^{a} y^{b})}^{c} \to (x^{a \cdot c} y^{b \cdot c})$ $(x^ay^b)^c -> (x^(a*c)y^(b*c))$

So in this example, all we have to do is distribute the $5$ $5$ to each of the exponents such as,

${(x^{2} y^{3})}^{5} \to (x^{2 \cdot 5} y^{3 \cdot 5}) = (x^{10} y^{15})$ $(x^2y^3)^5 -> (x^(2*5)y^(3*5)) = (x^10y^15)$

How do you simplify (x2⋅y3)5(x^2 * y^3) ^5?