How do you simplify ${(- x)}^{3} {(- 3 x^{2})}^{2}$ $(-x)^3 (-3x^2)^2$ ?

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Answer 1 · 2016-05-08T22:50:57

$- x^{3} \times 9 x^{4} = - 9 x^{7}$ $-x^3 xx 9x^4 = -9x^7$

Simplify each factor first....
${(- x)}^{3} = - x^{3}$ $(-x)^3 = -x^3" "$ NB - an odd number of negatives $\Rightarrow$ $rArr$ neg

${(- 3 x^{2})}^{2} = + 9 x^{4}$ $(-3x^2)^2 = +9x^4" "$ Square the -3 and the $x^{2}$ $x^2$

$:. -x^3 xx 9x^4 = -9x^7$

How do you simplify (-x)^3 (-3x^2)^2(−x)3(−3x2)2(-x)^3 (-3x^2)^2?