How do you simplify #(y-14)/(14-y)#?
1 Answer
Aug 13, 2016
Explanation:
What we want here is the numerator to be 14 - y, so that it can be
#color(blue)"cancelled"# with the 14 - y on the denominator.We can do this by factorising y - 14 as follows.
#y-14=-1(14-y)#
#rArr(y-14)/(14-y)=(-1cancel((14-y)))/cancel(14-y)=-1#
