How do you simplify #(y+2) /(y^2+2y-48) div(y+2)/(y^2-13y+42 )#?

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Answer 1 · 2018-06-14T11:46:57

When dividing fractions we Keep Flip Change (KFC!)

Keep the first fraction the same

#[y+2]/[y^2+2y-48]#

Flip the second fraction

#[y^2-13y+42]/[y+2]#

Change the #-:# sign to #xx#

#[y+2]/[y^2+2y-48] xx [y^2-13y+42]/[y+2]#

factorise

#[y+2]/[(y+8)(y-6)] xx [(y-6)(y-7)]/[y+2]#

cancel #(y-6)#

#[y+2]/(y+8) xx (y-7)/[y+2]#

cancel #(y+2)#

#1/(y+8) xx (y-7)/1#

multiply

#(y-7)/(y+8)#