How do you simplify $(y+2) /(y^2+2y-48) div(y+2)/(y^2-13y+42 )$ ?

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Answer 1 · 2018-06-14T11:46:57

When dividing fractions we Keep Flip Change (KFC!)

Keep the first fraction the same

$[y+2]/[y^2+2y-48]$

Flip the second fraction

$[y^2-13y+42]/[y+2]$

Change the $-:$ sign to $xx$

$[y+2]/[y^2+2y-48] xx [y^2-13y+42]/[y+2]$

factorise

$[y+2]/[(y+8)(y-6)] xx [(y-6)(y-7)]/[y+2]$

cancel $(y-6)$

$[y+2]/(y+8) xx (y-7)/[y+2]$

cancel $(y+2)$

$1/(y+8) xx (y-7)/1$

multiply

$(y-7)/(y+8)$

How do you simplify (y+2) /(y^2+2y-48) div(y+2)/(y^2-13y+42 )(y+2) /(y^2+2y-48) div(y+2)/(y^2-13y+42 )?