How do you simplify ${(- y^{3})}^{6}$ $(-y^ 3)^6$ ?

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Answer 1 · 2015-03-31T23:50:40

The answer is $y^{18}$ $y^18$ .

${(- y^{3})}^{6} = - y^{3 \cdot 6} = y^{18}$ $(-y^3)^6 = -y^(3*6) = y^18$

Because $- y^{3}$ $-y^3$ is multiplied times itself six times, an even number, it becomes positive.

$- y^{3} \cdot - y^{3} \cdot - y^{3} \cdot - y^{3} \cdot - y^{3} \cdot - y^{3} = y^{18}$ $-y^3*-y^3*-y^3*-y^3*-y^3*-y^3 = y^18$ .

How do you simplify (-y^ 3)^6(−y3)6(-y^ 3)^6?