How do you simplify $(y^{9}) {(2 y^{2})}^{3}$ $(y^9)(2y^2)^3$ ?

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Answer 1 · 2016-03-16T12:53:26

$= 8 y^{15}$ $= 8y^ 15$

$(y^{9}) {(2 y^{2})}^{3}$ $(y^9)(2y^2)^3$

$= y^{9} \cdot 2^{3} y^{(2 \cdot 3)}$ $= y^9 * color(blue)(2 ^3 y^( (2 *3) )$

$= y^{9} \cdot 8 \cdot y^{6}$ $= y^9 * 8 * y^ 6$

$= 8 y^{9} y^{6}$ $= 8y^9 y^ 6$

As per property:
$a^{m} \cdot a^{n} = a^{m + n}$ $color(blue)(a^m * a ^n = a ^(m+n)$

Applying the above to powers of $y$ $y$
$= 8 y^{9 + 6}$ $= 8y^ (9 +6)$

$= 8 y^{15}$ $= 8y^ 15$

How do you simplify (y^9)(2y^2)^3(y9)(2y2)3(y^9)(2y^2)^3?