How do you sketch one cycle of $y=4sin3x$ ?

Question

2733 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-10-10T04:10:31

$y=4sin 3x$
graph{4sin(3x) [-10, 10, -5, 5]}

$y=4sin3x$
$x=0,y=0$
$x=(pi/18), y=2$
$x=(pi/12), y=2sqrt2$
$x=(pi/9), y=2sqrt3$
$x=(pi/6), y=4$
$x=(pi/3), y=0$

How do you sketch one cycle of y=4sin3xy=4sin3x?