Question

How do you sketch one cycle of `y=cotx`?

Answer 1

Graph is inserted. See explanation.

Explanation:

The period ( cycle ) of cot x is `pi`.

In one cycle `x in (0, pi)`,

the ends `x= 0 and x = 0 and x = pi` are points if infinite

discontinuity. The midpoint is `(pi/2, 0)`

In the inserted graph, look for `x in (3.14, 0)`, for one cycle..

graph{cotx [-5, 5, -2.5, 2.5]}