How do you sketch the graph of $y= -0.1 sin (πx/10 + π)$ ?

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Answer 1 · 2018-05-04T03:52:45

As below.

$color(crimson)(y = A sin (Bx - C) + D$

$"Given " y = -0.1 sin ((pi/10) x + pi)$

$"Amplitude " = |A| = 0.1$

$"Period " = (2pi) / |B| = (2pi) / (pi/10) = 20$

$"Phase Shift " = -C / B = -pi / (pi/10) = -10, " 10 to the left"$

$"Vertical Shift " = D = 0$

graph{-0.1 sin((pi/10)x + pi) [-10, 10, -5, 5]}

How do you sketch the graph of y= -0.1 sin (πx/10 + π)y= -0.1 sin (πx/10 + π)?