How do you sketch $y=(x-3)(x+2)$ ?

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Answer 1 · 2016-12-17T08:32:19

Graph of the parabola is inserted.

y = quadratic in x or x = quadratic in y, the equation represents a

parabola.

The equation can be reorganized to the form

$(x-1/2)^2=y+25/4$ that represents a parabola,

with vertex at $(1/2, -25/4)$ , size a = 1/4 and axis $x = 1/2uarr.$

graph{y-(x-3)(x+2)=0 [-20, 20, -10, 10]}

How do you sketch y=(x-3)(x+2)y=(x-3)(x+2)?