How do you solve $0 = 18 x - 9 x^{2}$ $0=18x-9x^2$ ?

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Answer 1 · 2015-08-21T07:32:55

The solutions are
$x = 0$ $color(blue)(x=0$
$x = 2$ $color(blue)(x=2$

$0 = 18 x - 9 x^{2}$ $0=18x−9x^2$

$9 x^{2} - 18 x = 0$ $9x^2-18x=0$

$9 x$ $9x$ is common to both terms.

$9 x (x - 2) = 0$ $9x(x-2)=0$

The solutions are
$9 x = 0, x = 0$ $9x=0, color(blue)(x=0$
$x - 2 = 0, x = 2$ $x-2=0, color(blue)(x=2$

How do you solve 0=18x-9x^20=18x−9x20=18x-9x^2?