How do you solve $0 = 2 x^{2} + 32 x$ $0=2x^2+32x$ ?

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Answer 1 · 2018-04-04T19:55:10

$x = 0 or x = - 16$ $x=0 or x=-16$

Factorise $2 x (x + 16) = 0$ $2x(x+16)=0$

If two numbers multiply to make zero then one or both of them must be zero

$2 x = 0 or x + 16 = 0$ $2x=0 or x+16=0$

$x = 0 or x = - 16$ $x=0 or x=-16$

How do you solve 0=2x^2+32x0=2x2+32x0=2x^2+32x?