Question

How do you solve `0=4x^2 + 16x + 15`?

Answer 1

Solve y = 4x^2 + 16x + 15 (1)

Ans: -3/2 and -5/2

Explanation:

I use the new Transforming Method (Google Yahoo Search)
Transformed equation`y' = x^2 + 16x + 60.` (2)
Factor pairs of 60 --> ...(4, 15)(5, 12)(6, 10). This sum is 60 = b. Then, the 2 real roots of (2) are: -6 and -10.
Back to original equation (1), the 2 real roots are: `x1 = -6/4 = -3/2`, and `x2 = -10/4 = -5/2`.