How do you solve $0 = x^{2} + 5 x + 6$ $0 = x^2 + 5x + 6$ ?

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Answer 1 · 2015-05-26T12:20:38

Since $x^{2} + 5 x + 6$ $x^2+5x+6$ can be factored as
$(x + 1) (x + 5)$ $(x+1)(x+5)$

$0 = x^{2} + 5 x + 6$ $0 = x^2+5x+6$
is equivalent to
$(x + 1) (x + 5) = 0$ $(x+1)(x+5) = 0$

which implies
either $(x + 1) = 0$ $(x+1) = 0$ or $(x + 5) = 0$ $(x+5) = 0$

So
$x = - 1$ $x=-1$ or $x = - 5$ $x=-5$

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