How do you solve 1/2(m-6) = 3 + m/512(m6)=3+m5?

1 Answer
Apr 8, 2018

m = 20m=20

Explanation:

=> 1/2(m - 6) = 3 + m/512(m6)=3+m5

=> (m - 6)/2 = 3 + m/5m62=3+m5

=> m/2 - 6/2 = 3 + m/5m262=3+m5

=> m/2 - 3 = 3 + m/5m23=3+m5

=> m/2 - m/5 = 3 + 3m2m5=3+3

=> m[1/2 - 1/5] = 6m[1215]=6

=> m[(1/2 × 5/5) - (1/5 × 2/2)] = 6m[(12×55)(15×22)]=6

=> m[5/10 - 2/10] = 6m[510210]=6

=> m[(5 - 2)/10] = 6m[5210]=6

=> m(3/10) = 6m(310)=6

=> m = 6 × 10/(3) = cancel(3) × 2 × 10/cancel(3)

=> m = 20