How do you solve #1/2 (x-3) = 1/3 (2x+1)#?

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Answer 1 · 2015-06-01T20:00:19

#x/2-3/2=(2x)/3+1/3#

We are going to put it all on six by multiplying both denominators and numerators

#(3x)/6-9/6=(4x)/6+2/6#

We substract #2/6# on both sides

#(3x)/6-9/6-2/6=(4x)/6#

#(3x)/6-11/6=(4x)/6#

We substract #(3x)/6# on both side

#-11/6=(4x)/6-(3x)/6#

#-11/6=x/6#

We multiply both side by six to get #x#

#x=-11#