How do you solve #1/2k - 3 = 2 - 3/4k #?

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Answer 1 · 2018-03-04T16:42:52

The value of #k# is #4#.

Your equation is

#1/2k-3 = 2-3/4k#

Multiplying both sides by #4#, we get

#2k-12 = 8-3k#

Keeping the terms involving #k# on one side and the constants on the other, we get

#-12-8 = -3k-2k#

#-20 = -5k#

Divide both sides by #-5#

#(-20)/-5 = (-5k)/-5#

#4 = k#