How do you solve $- 1 \leq 2 x - 3 < 7$ $-1 <= 2x - 3 < 7$ ?

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Answer 1 · 2015-05-18T17:47:12

Isolate each inequality:

a. $- 1 \leq 2 x - 3 \to 2 x \geq 3 - 1 = 2 \to x \geq 1$ $-1 <= 2x - 3 -> 2x >= 3 - 1 = 2 -> x >= 1$

b. $2 x - 3 < 7 \to 2 x < 10 \to x < 5$ $2x - 3 < 7 -> 2x < 10 -> x < 5$

-------------------|0------|1============| 5----------------------

Note> The end (critical) point 1 is included in the solution set.

Solution half closed Interval [1, 5).

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