How do you solve $-1/3 <=(4x-1)/3< 1/2$ ?

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Answer 1 · 2015-07-26T21:07:11

Solve $- 1/3 <= (4x - 1)/3 < 1/2$

Ans: $0 <= x < 5/8$

$-1/3 <= (4x)/3 - 1/3 < 1/2$
$0<= (4x)/3 < 1/2 + 1/3 = 5/6$
$0 <= 4x < 15/6$
$0 < x < 15/24$
$0 <= x < 5/8$

---------------|0========|5/8----------------

Answer by half closed interval [0, 5/8)

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