How do you solve $1/3 abs(2c-5)+3=7$ ?

Question

1630 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-07-23T06:11:01

$c=-7/2 and c=17/2$

The given equation is equivalent to the following:

$1/3|2c-5|=-3+7$

$1/3|2c-5|=4$

$|2c-5|=12$

$2c-5=+-12$

$2c=5+-12$

$c=(5+-12)/2$

$c=-7/2 and c=17/2$

How do you solve 1/3 abs(2c-5)+3=7 1/3 abs(2c-5)+3=7 ?