How do you solve #10(x-7)^2=440#?

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Answer 1 · 2018-03-02T02:53:39

#x = 7-2sqrt(11), 7+2sqrt(11)#

Divide both sides by 10:

#(x-7)^2=44#

Take the square root of both sides

#x-7=+-sqrt(44)#

Add seven to both sides

#x=7+-sqrt(44)#

You can simplify the square root. A perfect square of #4# goes in there, so

#x=7+-2sqrt(11)#

Answer = #7-2sqrt(11), 7+2sqrt(11)#