How do you solve #-10a = - 72#?

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Answer 1 · 2016-12-06T21:30:14

#a = 36/5#

Divide each side of the equation to isolate #a# and keep the equation balanced. In this case we need to divide by #-10#:

#(-10a)/(-10) = (-72)/(-10)#

#(cancel(-10)a)/(cancel(-10)) = (-72)/(-10)#

#a = 72/10#

#a = (2/2) (36/5)#

#a = 1* 36/5#

#a = 36/5#