How do you solve $-10e^(2-2b)-6=-66$ ?

Question

2103 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-31T13:45:01

$b=0.104$

$-10e^(2-2b)-6=-66$

$hArr-10e^(2-2b)=-66+6$ or

$e^(2-2b)=(-60)/(-10)=6$ or

$2-2b=ln6$ or

$2b=2-ln6$ or

$b=1-ln6/2=1-1.792/2$

= $1-0.896=0.104$

How do you solve -10e^(2-2b)-6=-66-10e^(2-2b)-6=-66?