How do you solve $11 x^{2} - x - 3 = 0$ $11x^2 - x - 3 = 0$ ?

Question

How do you solve $11 x^{2} - x - 3 = 0$ $11x^2 - x - 3 = 0$ ?

1 Answer

Impact of this question

1570 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-08T14:57:22

$x = \frac{1}{22} \pm \frac{1}{22} \sqrt{133}$ $x=1/22+-1/22sqrt133$

Explanation:

$this quadratic does not factorise with whole number values$ $"this quadratic does not factorise with whole number values"$

$solve using the quadratic formula$ $"solve using the "color(blue)"quadratic formula"$

$∙ x x = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$ $•color(white)(x)x=(-b+-sqrt(b^2-4ac))/(2a)$

$11 x^{2} - x - 3 = 0 \leftarrow is in standard form$ $11x^2-x-3=0larrcolor(blue)"is in standard form"$

$with a = 11, b = - 1 and c = - 3$ $"with "a=11,b=-1" and "c=-3$

$\Rightarrow x = \frac{1 \pm \sqrt{1 + 132}}{22} = \frac{1 \pm \sqrt{133}}{22}$ $rArrx=(1+-sqrt(1+132))/22=(1+-sqrt133)/22$

$\Rightarrow x = \frac{1}{22} \pm \frac{1}{22} \sqrt{133} \leftarrow exact solutions$ $rArrx=1/22+-1/22sqrt133larrcolor(red)"exact solutions"$

$\Rightarrow x \approx - 0.48 or x \approx 0.57 to 2 dec. places$ $rArrx~~-0.48" or "x~~0.57" to 2 dec. places"$

Science

Math

Humanities

... and beyond

How do you solve $11 x^{2} - x - 3 = 0$ $11x^2 - x - 3 = 0$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you solve 11x^2 - x - 3 = 011x2−x−3=011x^2 - x - 3 = 0?

1 Answer

Explanation:

Related questions

Impact of this question

How do you solve $11 x^{2} - x - 3 = 0$ $11x^2 - x - 3 = 0$ ?