Question

How do you solve `12+11h= -18-4h`?

Answer 1

`h=-2`

Explanation:

`"collect terms in x on the left side and numeric value on"`
`"the right side"`

`"add 4h to both sides"`

`12+4h+11h=-18cancel(-4h)cancel(+4h)`

`rArr12+15h=-18`

`"subtract 12 from both sides"`

`cancel(12)cancel(-12)+15h=-18-12`

`rArr15h=-30`

`"divide both sides by 15"`

`(cancel(15) h)/cancel(15)=(-30)/15`

`rArrh=-2`

`color(blue)"As a check"`

Substitute this value into the equation and if both sides are equal then it is the solution.

`"left "=12+(11xx-2)=12-22=-10`

`"right "=-18-(4xx-2)=-18+8=-10`

`rArrh=-2" is the solution"`