How do you solve $12(x -4)-(x+2)=(x+2)(x-4)$ ?

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Answer 1 · 2016-05-12T23:06:17

First, distribute.

$12x - 48 - x - 2 = x^2 + 2x - 4x - 8$

$0 = x^2 - 13x + 40$

$0 = (x - 8)(x - 5)$

$x = 8 and 5$

Hopefully this helps!

How do you solve 12(x -4)-(x+2)=(x+2)(x-4)12(x -4)-(x+2)=(x+2)(x-4)?